First, perhaps the most relevant post
I had suggested surrounding a internally heated body with a froven - a fridge/oven giving active heating and cooling to a set temperature.
Also body and inner surface of froven are black bodies with same albedo
The post with clarification added!:
thefordprefect says: 2013/04/04 at 11:52 AM
[JP:... If the body has a heat source then it will stay at the temperature it was at without the oven heating it from a higher temperature. If the oven is cooler than the body than it can not heat the body. Photon quanta from a cooler source do not warm up a warmer source, even if they might exist. It is not a "sudden" cessation of effect when the oven becomes cooler than the body - it is a smooth transition in the direction of q, of heating.]
This cannot be correct.
If the temperature of the froven is warmer than the body you suggest it heats the body.
If the froven is cooler than the body you suggest it has no effect.
If the body is radiating quanta from a 100°C source then the hotter froven will be radiating to the body quanta from its 100C+ walls.
If the body is radiating quanta from a 100°C source then the cooler froven will be radiating nothing from it 100C- as if it were at absolute zero thats one heck of a sudden step.
Do I understand correctly?
[JP: Not quite yet. If the body is warmer than the oven, then the body heats the oven. If the oven is warmer than the body, then the oven heats the body. This is a smooth transition in the direction of heating as a function of the temperature differential: -2 -1 0 1 2 etc. A smooth transition, not a sudden stop.]
thefordprefect says: Your comment is awaiting moderation. 2013/04/05 at 11:52 AM
Seem to have problems posting so I’ll try again:
[JP: Not quite yet. If the body is warmer than the oven, then the body heats the oven. If the oven is warmer than the body, then the oven heats the body. This is a smooth transition in the direction of heating as a function of the temperature differential: -2 -1 0 1 2 etc. A smooth transition, not a sudden stop.]
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you have stated definitely that there is no transfer of energy from cold to hot:
“but what I do know is that they do NOT work by cold heating hot – hahaha what a stupid idea.”
“[JP Reply: Trashed because we've already answered you. q from the shell to the planet is 0. ZERO. There is no heat loss from the shell to the planet. Even if the shell is emitting on the inside, there is no heat loss to the planet. The only direction the shell can lose heat is outwards, and hence it loses the equivalent of 800 W/m2 outwards.]”
“Radiated energy does not equate to net heat transfer or even net energy transfer. The equation of heat flow for radiation, from physics, from actual physics textbooks and from actual universities and actual physics degrees, is q ~ (T2^4 – T1^4). If T2 = T1, then q = 0, and nothing heats up, even though there’s all that radiation. ”
So firstly I hope you would agree that the quanta of energy leaving a surface cannot depend on the final destination of the quanta i.e. its temperature, material and surface – it only depends on the source material and temperature.
I also believe this describes your point of view:
The final destination of the radiation determines what happens to the quanta (rejected or absorbed)
where 100C- a very very very! small bit less than 100C 100C+ a very very very! small bit more than 100C w greater than y
y greater than x
and x greater than z
oven at 101C transfers zero quanta to body at 10000C (equivalent to back radiation)
body at 10000C transfers w quanta to oven at 101C
body at 100C transfers zero quanta to oven at 101C (equivalent to back radiation)
oven at 101C transfers x quanta to body at 100C
oven at 100C- transfers zero quanta to body at 100C (equivalent to back radiation)
body at 100C transfers x quanta to oven at 101C-
oven at 100C+ transfers x+1 quanta to body at 100C
body at 100C transfers zero quanta to oven at 100C+ (equivalent to back radiation)
body at 100C transfers y quanta to oven at 99C
oven at 99C transfers zero quanta to body at 100C (equivalent to back radiation)
oven at 10000C transfers w quanta to body at 100C body at 100C transfers zero quanta to oven at 10000C (equivalent to back radiation)
at 100C- to 100C+ oven temperature the body quanta changes from outputting x to receiving x+1 quanta
.
Somehow this does not seem to be a smooth or logical transition
Warmists would say quanta emitted from an object depends only on the object and its temperature. the final destination of the radiation is immaterial (well actually the quanta knows nothing until it hits the surface)
The sum of all quanta determines the rate of loss/gain of heat
oven at 101C transfers y quanta to body at 10000C (equivalent to back radiation)
body at 10000C transfers w quanta to oven at 101C
oven at 101C transfers y quanta to body at 100C
body at 100C transfers x quanta to oven at 101C (equivalent to back radiation)
oven at 100C- transfers x-1 quanta to body at 100C (equivalent to back radiation)
body at 100C transfers x quanta to oven at 101C-
oven at 100C+ transfers x+1 quanta to body at 100C
body at 100C transfers x quanta to oven at 100C+ (equivalent to back radiation)
oven at 99C transfers z quanta to body at 100C (equivalent to back radiation)
body at 100C transfers x quanta to oven at 99C
oven at 10000C transfers w quanta to body at 100C
body at 100C transfers x quanta to oven at 10000C (equivalent to back radiation)
Consider 100C- to 100C+ oven temperature - the100C body quanta output is x and at 100C- it receives x-1 quanta and at 100C+ it receives x+1 quanta
A smooth and logical transition.
I assume that I have this wrong somehow so perhaps using x,y,z you could explain your position
[This last post did not get past moderation!]
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In pictures:
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| Assumed output from body and shell at 0K this is zero at 10K this is 100 quanta |
.
As the energy quanta increases from zero to 100 from body B with the temperature of B increasing from 0 to 10K
the energy quanta from shell A goes from 100 to zero as the temperature decreases from 10 to 0K
The temperature determines the quanta of energy released from the bodies
The warmist view would be that all energy from A gets absorbed by B and all energy from B gets absorbed by A irrespective of the temperature of each body
The Slayer version suggests that if the temperature of A is less than B then the transfer to B becomes zero/is reflected/cancels /nulled
and if the temperature of B is less than A then the transfer to A becomes zero/is reflected/cancels/nulled
This is shown in this diagram.
If one then looks at the net flow of quanta from A to B then the slayer version has a discontinuity where the temperatures are the same. The warmist version is a simple straight line which at B=A temperature the net transfer is zero.
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The whole thread
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